Sin75 + sin45/sin285 вычислите
sin(75°)+sin(45°)/sin(285°)=\=sin(30°+45°)+sin(45°)/(sin(180°+(60°+45°))=\=sin(30°)cos(45°)+cos(30°)sin45°)+sin(45°)/(−sin(60°+45°))=\=(1/2)∗(1/sqrt2)+(sqrt3)∗(1/sqrt2)+\+(1/sqrt2)/(−(sin(60°)cos(45°)+cos(60°)∗sin(45°)))=\=(1+sqrt3)/2sqrt2)+(1/sqrt2)/(−(sqrt3/2)(1/sqrt2)+(1/2)(1/sqrt2)=\=(1+sqrt3)/2sqrt2)+(1/sqrt2)/(−(1/sqrt2)((1+sqrt3)/2))=\=(1/2sqrt3)/2sqrt3)−2sqrt2)/(1+sqrt3)=\=(sqrt3−2)/(sqrt2+sqrt6)Похожие задачи: